(3y-4)(2y^2+y-1)=

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Solution for (3y-4)(2y^2+y-1)= equation: 


Simplifying
(3y + -4)(2y2 + y + -1) = 0

Reorder the terms:
(-4 + 3y)(2y2 + y + -1) = 0

Reorder the terms:
(-4 + 3y)(-1 + y + 2y2) = 0

Multiply (-4 + 3y) * (-1 + y + 2y2)
(-4(-1 + y + 2y2) + 3y * (-1 + y + 2y2)) = 0
((-1 * -4 + y * -4 + 2y2 * -4) + 3y * (-1 + y + 2y2)) = 0
((4 + -4y + -8y2) + 3y * (-1 + y + 2y2)) = 0
(4 + -4y + -8y2 + (-1 * 3y + y * 3y + 2y2 * 3y)) = 0
(4 + -4y + -8y2 + (-3y + 3y2 + 6y3)) = 0

Reorder the terms:
(4 + -4y + -3y + -8y2 + 3y2 + 6y3) = 0

Combine like terms: -4y + -3y = -7y
(4 + -7y + -8y2 + 3y2 + 6y3) = 0

Combine like terms: -8y2 + 3y2 = -5y2
(4 + -7y + -5y2 + 6y3) = 0

Solving
4 + -7y + -5y2 + 6y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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